At 1622 ZT on 15 June, in DR position LAT 10° 15.2' N, LONG 135° 10' W, you observe an amplitude of the Moon. The center of the Moon is on the visible horizon, bearing 101.2°psc. The variation is 5° E. What is the deviation?

Question

At 1622 ZT on 15 June, in DR position LAT 10&deg; 15.2' N, LONG 135&deg; 10' W, you observe an amplitude of the Moon. The center of the Moon is on the visible horizon, bearing 101.2&deg;psc. The variation is 5&deg; E. What is the deviation?

Accepted Answer

Option A: 1.5&deg;E. Calculate the Moon's declination and LHA. Determine the true amplitude using the standard formula sin(Amp) = sin(Dec) / cos(Lat). Convert the amplitude to a true bearing. Comparing this to the compass bearing (101.2° psc) and applying 5°E variation results in a deviation of 1.5°E.

At 1622 ZT on 15 June, in DR position LAT 10&deg; 15.2' N, LONG 135&deg; 10' W, you observe an amplitude of the Moon. The center of the Moon is on the visible horizon, bearing 101.2&deg;psc. The variation is 5&deg; E. What is the deviation?

At 1622 ZT on 15 June, in DR position LAT 10° 15.2' N, LONG 135° 10' W, you observe an amplitude of the Moon. The center of the Moon is on the visible horizon, bearing 101.2°psc. The variation is 5° E. What is the deviation?