On 10 February in DR position LAT 25°32.0'N, LONG 135°15.0'E, you observe an amplitude of the Sun. The Sun's center is on the celestial horizon and bears 109°psc. The chronometer reads 09h 43m 25s and is 03m 20s fast. Variation in the area is 4.5°W. What is the deviation of the standard magnetic compass?

Correct Answer: Option D — 1.6°E

Determine the Sun's declination and LHA to find the true amplitude. Compare the true amplitude to the compass bearing (109°psc) to find the total compass error. Subtract the 4.5°W variation from the compass error. The remaining value represents the deviation of the standard magnetic compass, calculated as 1.6°E.