On 12 June at 0919 zone time, your position is LAT 26°52'N, LONG 84°34'W. The chronometer reads 03h 17m 00s. Chronometer error is 01m 40s slow. At that time, an azimuth of the Sun is obtained. The bearing is 089.5° per standard magnetic compass. Variation for this area is 4.5°E. What is the deviation of the standard magnetic compass?

Question

On 12 June at 0919 zone time, your position is LAT 26&deg;52'N, LONG 84&deg;34'W. The chronometer reads 03h 17m 00s. Chronometer error is 01m 40s slow. At that time, an azimuth of the Sun is obtained. The bearing is 089.5&deg; per standard magnetic compass. Variation for this area is 4.5&deg;E. What is the deviation of the standard magnetic compass?

Accepted Answer

Option D: 5.2&deg;W. Calculate the Sun's declination and LHA to determine the true amplitude. Using the formula sin(Amp) = sin(Dec) / cos(Lat), find the true bearing. Applying the variation of 4.5°E to the compass bearing of 089.5°psc, the deviation is found by comparing the true bearing to the magnetic bearing, resulting in 5.2°W.