On 16 April in DR position LAT 28°07.0'N, LONG 81°47.0'W, you observe an amplitude of the Sun. The Sun's center is on the visible horizon and bears 073.5°psc. The chronometer reads 10h 53m 41s and is 02m 23s slow. Variation in the area is 11°E. What is the deviation of the magnetic compass?

Question

On 16 April in DR position LAT 28&deg;07.0'N, LONG 81&deg;47.0'W, you observe an amplitude of the Sun. The Sun's center is on the visible horizon and bears 073.5&deg;psc. The chronometer reads 10h 53m 41s and is 02m 23s slow. Variation in the area is 11&deg;E. What is the deviation of the magnetic compass?

Accepted Answer

Option D: 6.5&deg;W. Calculate the Sun's declination and LHA. Determine the true amplitude using sin(Amp) = sin(Dec) / cos(Lat). Convert the amplitude to a true bearing. Comparing this to the compass bearing (073.5° psc) and applying 11°E variation results in a deviation of 6.5°W.