On 17 April your 1516 zone time DR position is LAT 27°24.0'N, LONG 115°24.0'E. At that time, you observe the Sun bearing 247°psc. The chronometer reads 07h 16m 26s, and the chronometer error is 00m 32s slow. The variation is 4.5°E. What is the deviation of the standard compass?

Question

On 17 April your 1516 zone time DR position is LAT 27&deg;24.0'N, LONG 115&deg;24.0'E. At that time, you observe the Sun bearing 247&deg;psc. The chronometer reads 07h 16m 26s, and the chronometer error is 00m 32s slow. The variation is 4.5&deg;E. What is the deviation of the standard compass?

Accepted Answer

Option B: 5.4&deg;E. Compute the Sun's true azimuth for the given time and position. The difference between the true azimuth and the compass bearing of 247°psc establishes the compass error. Adjusting for 4.5°E variation using the formula Error = Variation + Deviation confirms a deviation of 5.4°E for the standard magnetic compass.

On 17 April your 1516 zone time DR position is LAT 27&deg;24.0'N, LONG 115&deg;24.0'E. At that time, you observe the Sun bearing 247&deg;psc. The chronometer reads 07h 16m 26s, and the chronometer error is 00m 32s slow. The variation is 4.5&deg;E. What is the deviation of the standard compass?

On 17 April your 1516 zone time DR position is LAT 27°24.0'N, LONG 115°24.0'E. At that time, you observe the Sun bearing 247°psc. The chronometer reads 07h 16m 26s, and the chronometer error is 00m 32s slow. The variation is 4.5°E. What is the deviation of the standard compass?