On 23 August in DR position LAT 24°07.0'N, LONG 136°16.0'E, you observe an amplitude of the Sun. The Sun's center is on the visible horizon and bears 074.5°psc. The chronometer reads 08h 56m 19s and is 02m 34s fast. Variation in the area is 2°W. What is the deviation of the magnetic compass?

Question

On 23 August in DR position LAT 24&deg;07.0'N, LONG 136&deg;16.0'E, you observe an amplitude of the Sun. The Sun's center is on the visible horizon and bears 074.5&deg;psc. The chronometer reads 08h 56m 19s and is 02m 34s fast. Variation in the area is 2&deg;W. What is the deviation of the magnetic compass?

Accepted Answer

Option C: 4.5&deg;E. Calculate the Sun's declination and LHA via the Nautical Almanac. Determine the true amplitude using sin(Amp) = sin(Dec) / cos(Lat). Convert the true amplitude to a true bearing. Comparing this to the compass bearing (074.5° psc) and applying 2°W variation yields a deviation of 4.5°E.