On 28 September in DR position LAT 27°16.7'S, LONG 113°27.2'W, you observe an amplitude of the Sun. The Sun's center is on the celestial horizon and bears 273°psc. The chronometer reads 01h 17m 26s and is 01m 49s slow. Variation in the area is 6°W. What is the deviation of the standard magnetic compass?

Correct Answer: Option D — 0.4°E

Calculate the LHA and declination to find the True Amplitude. Compare the True Amplitude (Zn) to the Compass Amplitude (psc) to find the compass error. Applying the variation of 6°W to the compass error (True = Compass + Error) isolates the deviation. The resulting calculation confirms a deviation of 0.4°E.