On 4 July your vessel's 1722 zone time DR position is LAT 34°30'S, LONG 174°48'E, when an amplitude of the Sun is observed. The sun's center is on the visible horizon and bears 282° per standard magnetic compass. Variation in the area is 17.2°E. The chronometer reads 05h 21m 48s and is 02m 01s fast. What is the deviation of the compass?

Correct Answer: Option C — 1.5°W

Determine Greenwich Hour Angle and declination using the Nautical Almanac, then apply the amplitude formula $\sin(\text{Amp}) = \frac{\text{sin(Dec)}}{\cos(\text{Lat})}$. This yields true bearing. Comparing true bearing with magnetic bearing and applying variation (17.2°E) reveals a compass deviation of 1.5°W.