To check stability, a weight of 10 tons is lifted with the jumbo boom whose head is 45 ft. from the ship's centerline. The clinometer show's a list of 5.0° with weight suspended. Displacement including the weight is 9,000 tons. What would be the GM in this condition?

Correct Answer: Option A — 0.57 foot

Transverse stability during a weight shift using a jumbo boom applies GM = (w * d) / (W * tan(list)). Computing (10 tons * 45 ft) divided by (9000 tons * tan(5.0°)) provides the correct metacentric height of 0.57 foot for this loading condition.