To check stability, a weight of 40 tons is lifted with the jumbo boom, whose head is 40 feet from the ship's centerline. The clinometer shows a list of 6.5° with the weight suspended. Displacement including weight is 16,000 tons. What would be the GM while in this condition?

Question

To check stability, a weight of 40 tons is lifted with the jumbo boom, whose head is 40 feet from the ship's centerline. The clinometer shows a list of 6.5&deg; with the weight suspended. Displacement including weight is 16,000 tons. What would be the GM while in this condition?

Accepted Answer

Option C: 0.88 foot. Apply the standard stability formula GM = (w * d) / (Displacement * tan(theta)). With a 40-ton weight at a 40-foot distance and a displacement of 16,000 tons at a 6.5-degree list: (40 * 40) / (16000 * tan(6.5 degrees)) = 1600 / (16000 * 0.1139) = 1600 / 1822.4 = 0.877 feet, which rounds to 0.88 feet.

To check stability, a weight of 40 tons is lifted with the jumbo boom, whose head is 40 feet from the ship's centerline. The clinometer shows a list of 6.5&deg; with the weight suspended. Displacement including weight is 16,000 tons. What would be the GM while in this condition?

To check stability, a weight of 40 tons is lifted with the jumbo boom, whose head is 40 feet from the ship's centerline. The clinometer shows a list of 6.5° with the weight suspended. Displacement including weight is 16,000 tons. What would be the GM while in this condition?