You are hoisting a heavy lift with the jumbo boom. Your vessel displaces 5230 T. The 35-ton weight is on the pier and its center is 60' to starboard of the centerline. The head of the boom is 105' above the base line and the center of gravity of the lift when stowed on deck will be 42' above the base line. As the jumbo boom takes the strain the ship lists to 5°. What is the GM with the cargo stowed?

Question

You are hoisting a heavy lift with the jumbo boom. Your vessel displaces 5230 T. The 35-ton weight is on the pier and its center is 60' to starboard of the centerline. The head of the boom is 105' above the base line and the center of gravity of the lift when stowed on deck will be 42' above the base line. As the jumbo boom takes the strain the ship lists to 5&deg;. What is the GM with the cargo stowed?

Accepted Answer

Option C: 4.98. Applying the stability formula GM = (w * d) / (Δ * tan θ), where w is 35 tons, d is 60 feet, and Δ is 5230 tons at a 5-degree list. The calculation (35 * 60) / (5230 * tan 5°) results in a GM of approximately 4.98 feet, confirming the vessel's stability during the lift.