Q6 (10 Marks) Electrical Circuits & Calculations
MET • Written Exam

(a) What is meant by "Resonance" in RLC circuits? Compare the series and parallel resonance circuits. (10)

(b) Find the frequency at which the following circuit resonates. (6)

Appeared In: Aug 2019

Verified Model Answer (Text Solution)

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Part (a)

Resonance in RLC circuits, and comparison of series and parallel resonance:

  • Resonance is the condition in an RLC circuit when the inductive reactance equals the capacitive reactance (XL = XC). At resonance the circuit is purely resistive, the impedance is a minimum (series) or maximum (parallel), and the current is in phase with the voltage.
  • Series resonance: XL = XC, so the impedance Z = R (minimum). The current is a maximum and equals V/R. The voltage across the inductor and capacitor can be much larger than the supply voltage (voltage magnification). The resonant frequency f0 = 1/(2 pi sqrt(LC)). The power factor is unity.
  • Parallel resonance: XL = XC, so the admittance is a minimum and the impedance is a maximum. The line current is a minimum, while the circulating current in the L-C branch can be large (current magnification). The resonant frequency is approximately f0 = 1/(2 pi sqrt(LC)). The power factor is unity.
  • Comparison: in series resonance the impedance is minimum and current maximum; in parallel resonance the impedance is maximum and current minimum. Series resonance gives voltage magnification; parallel resonance gives current magnification. Series resonance is used in tuned circuits and filters; parallel resonance is used in rejector circuits and to improve power factor.
Part (b)

Frequency at which the circuit resonates:

  • The resonant frequency of an RLC circuit is f0 = 1/(2 pi sqrt(L C)), where L is the inductance in henries and C the capacitance in farads.
  • (The numerical value depends on the values of L and C given in the figure; the method is to substitute the given L and C into f0 = 1/(2 pi sqrt(LC)).)
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