Q6 (10 Marks) Ship Stability
SC&S • Written Exam

(a) Define Centre of Buoyancy and show with the aid of sketches how a vessel which is stable will return to the upright after being heeled by an external force (6)

(b) An oil tanker of 17000 tonne displacement has its centre of gravity 1m aft of midships and has 250 tonne of oil fuel in its forward deep tank 75m from midhships. This fuel is transferred to the after oil fuel bunker whose centre is 50m from midships. 200 tonne of fuel from the after bunker is now burned.

Calculate the new position of the centre of gravity (10)

(a) After the oil has been transferred

(b) After the oil has been used

Appeared In: Sep 2022

Verified Model Answer (Text Solution)

Structured for DG Shipping MEO Class II examination scoring criteria.

Exam Ready
Part (a)

Centre of buoyancy and how a stable vessel returns to the upright.

The centre of buoyancy (B) is the centre of gravity of the displaced volume of water, i.e. the point through which the resultant of the buoyancy forces acts. For a floating ship it lies on the vertical through the centre of gravity when the ship is upright. When the ship is heeled by an external force, the shape of the displaced volume changes and the centre of buoyancy moves to the low side. The buoyancy force acts vertically upwards through the new centre of buoyancy, while the weight acts vertically downwards through the centre of gravity. If the centre of buoyancy moves such that the buoyancy force acts on the high side of the centre of gravity, a righting couple (Delta x GZ) is produced that returns the ship to the upright. Sketch: the ship heeled, with the centre of gravity G and the new centre of buoyancy B', the buoyancy force acting vertically through B' and the weight through G, producing a righting moment that returns the ship to the upright. The ship is stable if the metacentre M is above G (GM positive).

Part (b)

New position of the centre of gravity of an oil tanker.

An oil tanker of 17,000 t displacement has its centre of gravity 1 m aft of midships and has 250 t of oil fuel in its forward deep tank 75 m from midships. This fuel is transferred to the after oil fuel bunker whose centre is 50 m from midships. 200 t of fuel from the after bunker is now burned. Calculate the new position of the centre of gravity (a) after the oil has been transferred, (b) after the oil has been used.

Take aft as positive. Initial CG = +1 m (1 m aft of midships). Forward deep tank at -75 m (75 m forward), after bunker at +50 m.

Part (a)

After transfer of 250 t from -75 m to +50 m:

The shift of the CG = w x (change in position)/Delta = 250 x (50 - (-75))/17000 = 250 x 125/17000 = 31,250/17,000 = 1.838 m aft.

New CG = 1 + 1.838 = 2.838 m aft of midships.

Part (b)

After burning 200 t from the after bunker (+50 m):

Removing 200 t from +50 m shifts the CG forward. The new displacement = 17,000 - 200 = 16,800 t.

New CG = (17,000 x 2.838 - 200 x 50)/16,800 = (48,246 - 10,000)/16,800 = 38,246/16,800 = 2.277 m aft of midships.

Answer: (a) CG is 2.84 m aft of midships after transfer; (b) CG is 2.28 m aft of midships after burning 200 t.

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