Q7 (10 Marks) Ship Stability
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A ship 90 m long displaces 5200 tone and floats at draughts of 4.95 m forward and 5.35 m aft when in sea water of 1023 Kg/m2. The waterplane area is 1100m2, GMl 95m, LCB 0.6m forward of midships and LCF 2.2m aft of midships. Calculate the new draughts when the vessel moves into fresh water of 1002 Kg/m3

Appeared In: Dec 2018

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Given:

$$L\:=\:90m$$

$$\Delta\:=\:5200\:tonnes$$

$$d_{f}=\:4.95m$$

$$d_{a}=\:5.35m$$

$$\rho_{sw}=\:1023kg/m^3$$

$$A_{w}=1100m^2$$

$$G_{ML}=\:95cm$$

$$LCB=\:0.6m\:fwd\:of\:midship\:$$

$$LCF=\:2.2m\:aft\:of\:midship$$

$$when\:vessel\:moves\:into\:fresh\:water\:of\:density\:1002kg/m^3$$

$$new\:drafts\:=\:?$$

$$\mathbf{Change\:in\:mean\:draft\:due\:to\:change\:in\:density\:}$$

$$=\:\frac{100\times\Delta}{A_{w}}\left\lbrack\frac{\rho_{s}\:-\:\rho_{r}}{\rho_{s}\times\rho_{r}}\right\rbrack$$

$$=\:\frac{100\:\times5200}{1100}\left\lbrack\frac{1.023\:-\:1.002}{1.023\:\times1.002}\right\rbrack=\:9.68\times10^{-3}m$$

$$Change\:in\:mean\:draft=\:9.7cm$$

$$MCT_{1cm}=\frac{\Delta\:\times GM_{}_{L}}{100\:\times L}$$

$$=\:\frac{5200\:\times95}{100\:\times90}$$

$$MCT_{1cm}=\:54.88\:ton.\:m$$

$$\mathbf{Change\:in\:trim\:when\:vessel\:moves\:from\:SW\:to\:FW}$$

$$=\:\frac{\Delta\times FB}{MCT_{1cm}}\left\lbrack\frac{\rho_{s}-\rho_{r}}{\rho_{s}}\right\rbrack$$

$$FB\:=\:LCF\:+\:LCB$$

$$FB\:=\:2.2\:+\:0.6\:=\:2.8m$$

$$=\:\frac{5200\:\times2.8}{54.88}\left\lbrack\frac{1.023\:-\:1.002}{1.023}\right\rbrack\:=\:5.44\:\times10^{-3}$$

$$Change\:in\:trim\:=\:5.45cm\:by\:head$$

$$\bm{When\:trim\:by\:head,\:change\:in\:fwd\:draft}$$

$$d_{f}=\frac{+t}{L}\left\lbrack\frac{L}{2}+LCF\right\rbrack$$

$$=\:\frac{5.45}{90}\left\lbrack\frac{90}{2}+2.2\right\rbrack$$

$$d_{f}=\:2.858cm$$

$$\bm{When\:trim\:by\:head,\:change\:in\:aft\:draft}$$

$$d_{a}=\:\frac{-t}{L}\left\lbrack\frac{L}{2}-LCF\right\rbrack$$

$$=\:\frac{-5.45}{90}\left\lbrack\frac{90}{2}-2.2\right\rbrack$$

$$d_{a}=\:-2.59cm$$

New draught fwd = draft fwd + change in mean trim + change in fwd draft

$$=\:4.95\:+\:0.097+0.02858\:$$

$$D_{f}=\:5.076m$$

$$New\:aft\:draft\:=\:5.35+0.097-0.0259\:$$

$$D_{a}=5.421m$$

$$\bm{New\:fwd\:draft\:D_{f}=5.076m}$$

$$\bm{New\:aft\:draft\:D_{a}=\:5.421m}$$

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