Q8 (10 Marks) Ship Stability
SC&S • Written Exam

(a) Describe how the force on the ship's bottom and the GM vary when grounding takes place. (6)

(b) The 1/2 ordinates of a waterplane at 15 m intervals, commencing from aft, are 1, 7, 10.5, 11, 11, 10.5, 8, 4 and 0 m. Calculate: (10)

(i) ТРC

(ii) Distance of the centre of flotation from midships

(iii) Second moment of area of the waterplane about a transverse axis through the centre of flotation.

Appeared In: Nov 2022

Verified Model Answer (Text Solution)

Structured for DG Shipping MEO Class II examination scoring criteria.

Exam Ready
Part (a)

When a ship grounds, the forces on the bottom and the metacentric height (GM) change depending on the grounding's nature and the ship's position on the seabed.

If the ship grounds on a level bottom:

  • A ground reaction force acts vertically upwards from the seabed. This force counteracts part of the ship's weight and alters the distribution of buoyancy forces.
  • The ship’s centre of gravity (G) may appear to rise relative to the metacentre (M) because the upward ground reaction reduces the buoyancy force acting on the underwater volume.
  • This virtual rise in G reduces GM, potentially leading to a list.
  • If the list becomes excessive and the righting moment is insufficient, the ship may capsize.

If the ship grounds on a pinnacle:

  • The ship experiences two forces at the ship's bottom:
    • A downward force due to the ship’s weight.
    • An upward reaction force is concentrated on the pinnacle.
  • The resulting force between the grounding pressure and the ship’s centre of buoyancy shifts downward towards the pinnacle.
  • This situation is similar to when the ship's stern touches the keel block in a dry dock.
  • A virtual loss of GM occurs because the ship’s inclining moment may exceed the maximum righting lever.
  • If the inclining moment is too great, the ship may develop an excessive list or even capsize.
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