Q9 (16 Marks) Ship Stability
SC&S • Written Exam

(a) Explain why the rudder angle does not normally exceeds 35°. (6)

(b) A ship of 12000 tonne displacement has a rudder 15m² in area, whose centre is 5m below the waterline. The metacentric height of the ship is 0.3m and the centre of buoyancy is 3.3m below the waterline. When travelling at 20 knots the rudder is turned through 30°. Find the initial angle of heel if the force Fn is perpendicular to the plane of the rudder is given by: F = 577 Av² sin α.

Allow 20% for the race effect. (10)

Appeared In: Jul 2025

Verified Model Answer (Text Solution)

Structured for DG Shipping MEO Class II examination scoring criteria.

Exam Ready
Part (a)

Why the rudder angle does not normally exceed 35 degrees.

The rudder is most effective at moderate angles. As the helm angle increases, the lift (normal force) on the rudder rises up to about 30-35 degrees, beyond which the flow separates from the rudder surface, the lift falls off and the drag rises sharply (stall). The rudder force also produces a heeling moment and increases resistance. Beyond about 35 degrees the additional turning effect is negligible or negative, while the drag and heeling moment increase, so there is no benefit in a larger angle. Hence the maximum rudder angle is limited to about 35 degrees (SOLAS requires the rudder to be capable of being put hard over to 35 degrees in 28 seconds), giving the best turning performance with acceptable drag and heel.

Part (b)

Rudder heeling angle.

Data: displacement 12,000 t; rudder area A = 15 m2; rudder centre 5 m below the waterline; GM = 0.3 m; centre of buoyancy 3.3 m below the waterline; speed 20 knots; helm angle 30 deg; force Fn = 577 A v2 sin(alpha); allow 20% race effect.

Speed: v = 20 x 0.5144 = 10.29 m/s, v2 = 105.84.

Fn = 577 x 15 x 105.84 x 0.5 = 458,035 N.

Race effect 20%: F = 1.2 x 458,035 = 549,642 N.

Heeling moment = F x lever = 549,642 x 5 = 2,748,210 Nm (lever = 5 m, the rudder centre below the waterline).

tan(theta) = (F x lever)/(W x GM) = 2,748,210/(12000 x 9810 x 0.3) = 2,748,210/35,316,000 = 0.07782.

theta = atan(0.07782) = 4.45 deg.

Answer: initial angle of heel about 4.5 deg.

← Back to SC&S Question Bank Upload Recent Question Paper →