A jack-up 210 feet in length is level during transit. The LCF is 140 feet aft of the bow. How much weight should be applied at the bow to level the jack-up if 150 kips are loaded at the transom?

Correct Answer: Option B — 75 kips

Using moments about the Longitudinal Center of Flotation (LCF): Transom moment = 150 kips × (Length - LCF distance) = Bow moment required to maintain trim. With LCF at 140 ft from a 210 ft bow, balancing forces requires 75 kips applied at the bow.