A jack-up with a calculated moment to change list one inch (MCL1") of 1,200 foot- kips intends to transfer 100 kips of weight in a transverse direction. How far should the weight be transferred to change the draft on the port side from 11.5 to 11.0 feet?

Correct Answer: Option D — 144 feet

A 0.5-foot (6-inch) draft change requires a moment of 6 inches multiplied by 1,200 foot-kips, totaling 7,200 foot-kips. Dividing this required moment by the weight of 100 kips gives the necessary shift distance. 7,200 divided by 100 equals 144 feet, the distance the weight must be moved transversely.