A MODU displacing 30,500 long tons has a KG of 60 feet. A weight of 500 long tons is discharged from a VCG of 150 feet. What is the change in KG?

Correct Answer: Option C — 1.5 feet downward

The change in center of gravity resulting from weight discharge is calculated using the formula $\Delta KG = \frac{w \times (KG - vcg)}{W - w}$. Substituting the values: $\frac{500 \times (60 - 150)}{30,500 - 500} = \frac{-45,000}{30,000} = -1.5$ feet, representing a 1.5-foot downward shift.