A vessel at LAT 14°10'N, LONG 61°00'W is to proceed to LAT 10°00'N, LONG 53°23'W. What is the course and distance by mid-latitude sailing?

Correct Answer: Option A — 119.2°T, 512.0 miles

Mid-latitude sailing utilizes the mean latitude to convert departure into difference of longitude. With a difference of latitude of 250' and a departure of 486.5', the formula tan(Course) = Departure / DLat yields 119.2°T, while the distance is calculated as DLat / cos(Course), resulting in 512.0 miles.