Deck General USCG Question #4442 (Set 142)

An elevated jack-up weighs 14,000 kips. Its TCG is located 1.0 foot to port of the centerline. What would be the new TCG for the jack-up if the drill floor, weighing 700 kips, is skidded 10 feet to starboard?

Official USCG Answer & Rule Citation

Correct Answer: Option D — 0.50 foot port

Transverse center of gravity shift is calculated using the formula: dTCG = (w * d) / W. Shifting a 700-kip drill floor 10 feet starboard on a 14,000-kip jack-up moves the center 0.50 feet starboard, changing the TCG from 1.0 foot port to 0.50 foot port.

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