An elevated jack-up weighs 14,000 kips. Its TCG is located 1.0 foot to starboard of the centerline. What would be the new TCG for the jack-up if the drill floor, weighing 700 kips, is skidded 10 feet to port?

Correct Answer: Option B — 0.50 foot starboard

Transverse center of gravity is determined by summing transverse moments and dividing by total weight. Initial moment is 14,000 kips × 1.0 ft = +14.0 ft-kips. Shifting 700 kips 10 ft to port gives -7,000 ft-kips. Net moment is +7,000 ft-kips. Divided by 14,000 kips yields 0.50 foot starboard.