An elevated jack-up weighs 14,000 kips. The drill floor, weighing 700 kips, is skidded 10.0 feet to starboard. The change in TCG is __________.

Correct Answer: Option B — 0.50 foot starboard

Transverse center of gravity shift is calculated using the formula $\Delta TCG = \frac{w \times d}{W}$. Substituting the given values: $\frac{700 \text{ kips} \times 10.0 \text{ ft}}{14,000 \text{ kips}} = 0.50$ foot to starboard. This fundamental stability principle governs weight movement across the centerline.