Deck General USCG Question #4551 (Set 146)

An elevated jack-up weighs 17,000 kips. Its center of gravity is located 110 feet aft of frame zero (AF0). What would be the new LCG if the cantilever (weight 900 kips) and drill floor (weight 800 kips) were skidded 70 feet aft?

Official USCG Answer & Rule Citation

Correct Answer: Option C — 117.0 feet AF0

New Longitudinal Center of Gravity is calculated using standard moment summation: $\text{New LCG} = \frac{\Sigma (W \times d)}{\text{Total Weight}}$. Factoring the combined cantilever and drill floor weight of 1,700 kips shifted 70 feet aft against the initial 17,000-kip unit weight yields 117.0 feet AF0.

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