Navigation Problems USCG Question #1878 (Set 56)

At 1430 ZT on 16 April, in DR position LAT 34° 03.8'N, LONG 061° 02.5'W, you observe an amplitude of the Moon. The center of the Moon is on the visible horizon and bears 095.2°psc. The variation is 12°W. What is the deviation?

Official USCG Answer & Rule Citation

Correct Answer: Option D — 1.9°E

Compass deviation is found by comparing true bearing from celestial amplitude tables with compass bearing. True bearing (097.1°T) adjusted for 12°W variation yields magnetic 109.1°M. Comparing with 095.2°psc results in a deviation of 1.9°E using 'Compass least, East best'.

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