At 1542 ZT on 23 October, in DR position LAT 37° 28.5'N, LONG 156° 17.3'E, you observe an amplitude of the Moon. The center of the Moon is on the visible horizon and bears 282.5°psc. The variation is 0.0°. What is the deviation?

Correct Answer: Option B — 2.2°E

Moon amplitudes require applying lunar parallax and semi-diameter corrections from the Nautical Almanac. Solving the amplitude relation $\sin(\text{Amp}) = \frac{\text{sin(Dec)}}{\cos(\text{Lat})}$ provides true bearing. Comparing true bearing against standard compass bearing with 0.0° variation yields 2.2°E deviation.