At 1610 ZT on 14 August, in DR position LAT 33° 24.6'S, LONG 028°15.4'W, you observe an amplitude of the Moon. The center of the Moon is on the visible horizon and bears 111.0° psc. The variation is 2°E. What is the deviation?

Question

At 1610 ZT on 14 August, in DR position LAT 33&deg; 24.6'S, LONG 028&deg;15.4'W, you observe an amplitude of the Moon. The center of the Moon is on the visible horizon and bears 111.0&deg; psc. The variation is 2&deg;E. What is the deviation?

Accepted Answer

Option B: 1.1&deg;W. Convert zone time to GMT to access precise lunar ephemeris. Solve the celestial amplitude equation incorporating latitude and lunar declination to find true bearing. Contrast this true value with the psc bearing and variation to compute deviation.

At 1610 ZT on 14 August, in DR position LAT 33&deg; 24.6'S, LONG 028&deg;15.4'W, you observe an amplitude of the Moon. The center of the Moon is on the visible horizon and bears 111.0&deg; psc. The variation is 2&deg;E. What is the deviation?

At 1610 ZT on 14 August, in DR position LAT 33° 24.6'S, LONG 028°15.4'W, you observe an amplitude of the Moon. The center of the Moon is on the visible horizon and bears 111.0° psc. The variation is 2°E. What is the deviation?