At 2048 ZT on 13 October you are in DR position LAT 44°02.8' S, LONG 146°58.3' E, when you observe an amplitude of Venus. The planet is about one Sun's diameter above the visible horizon and bears 222.2°psc. The variation is 15°E. What is the deviation?

Correct Answer: Option D — 1.0°W

Determine the true bearing of Venus via amplitude calculations for the given latitude and declination. Compare true azimuth against standard compass bearing (222.2°psc) to find total compass error, then apply variation (15°E) to resolve deviation as 1.0°W.