At 2326 ZT on 22 June, your vessel's position is LAT 28°30'N, LONG 150°04'W. An azimuth of the planet Jupiter is observed, and the standard compass bearing is 250.4°. The chronometer reads 09h 24m 36s and is 01m 12s slow. The variation of this area is 13.5°E. What is the deviation of the standard compass?

Correct Answer: Option A — 2.3°E

Planet Jupiter sight reduction provides a true azimuth when processed with accurate Greenwich Mean Time and position data. Comparing the computed true bearing against the standard compass bearing and applied variation isolates the remaining error, confirming a deviation of 2.3°E.