At 2326 ZT on 22 June, your vessel's position is LAT 28°30'N, LONG 150°04'W. An azimuth of the planet Jupiter is observed, and the standard compass bearing is 250.4°. The chronometer reads 09h 24m 36s and is 01m 12s slow. The variation of this area is 13.5°E. What is the deviation of the standard compass?

Question

At 2326 ZT on 22 June, your vessel's position is LAT 28&deg;30'N, LONG 150&deg;04'W. An azimuth of the planet Jupiter is observed, and the standard compass bearing is 250.4&deg;. The chronometer reads 09h 24m 36s and is 01m 12s slow. The variation of this area is 13.5&deg;E. What is the deviation of the standard compass?

Accepted Answer

Option D: 2.3&deg;E. Calculate the LHA of Jupiter using the chronometer time and GHA/Dec from the Nautical Almanac. Determine the True azimuth of the body. Using the formula True = Compass + Variation + Deviation, and knowing the variation is 13.5° E, the deviation is calculated as 2.3° E to match the observed compass bearing.