Navigation Problems USCG Question #400 (Set 11)

If the speed necessary for reaching port at a designated time is 12.6 knots and the pitch of the propeller is 13.6 feet, how many revolutions per minute will the shaft have to turn, assuming no slip?

Official USCG Answer & Rule Citation

Correct Answer: Option D — 94 RPM

With zero slip, the formula simplifies to: (Knots × 6,076.1) / (Pitch × 60). Using 12.6 knots and 13.6' pitch: (12.6 × 6,076.1) / (13.6 × 60) = 76,558.86 / 816 = 93.8 RPM. Rounding to the nearest whole number provides 94 RPM, matching the examination key.

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