On 1 September your 1115 zone time DR position is LAT 25°20.0'N, LONG 28°24.0'W. At that time, you observe the Sun bearing 160.5°psc. The chronometer reads 01h 14m 58s, and the chronometer error is 01m 17s fast. The variation is 13.5°W. What is the deviation of the standard compass?

Correct Answer: Option C — 2.1°E

Determine GMT using chronometer reading and error, and retrieve celestial coordinates from the Nautical Almanac. Solve the PZX triangle following Bowditch to find the true azimuth of the Sun. Combine true bearing with variation (13.5°W) and compass bearing (160.5°psc) to compute the 2.1°E compass deviation.