On 1 September your 1115 zone time DR position is LAT 25°20.0'N, LONG 28°24.0'W. At that time, you observe the Sun bearing 160.5°psc. The chronometer reads 01h 14m 58s, and the chronometer error is 01m 17s fast. The variation is 13.5°W. What is the deviation of the standard compass?

Question

On 1 September your 1115 zone time DR position is LAT 25&deg;20.0'N, LONG 28&deg;24.0'W. At that time, you observe the Sun bearing 160.5&deg;psc. The chronometer reads 01h 14m 58s, and the chronometer error is 01m 17s fast. The variation is 13.5&deg;W. What is the deviation of the standard compass?

Accepted Answer

Option A: 2.1&deg;E. Calculate the Sun's true azimuth for the given time and position. Compare this true azimuth to the observed compass bearing (160.5 degrees psc) to determine the compass error. Applying the 13.5 degrees West variation to the total compass error results in a deviation of 2.1 degrees East.

On 1 September your 1115 zone time DR position is LAT 25&deg;20.0'N, LONG 28&deg;24.0'W. At that time, you observe the Sun bearing 160.5&deg;psc. The chronometer reads 01h 14m 58s, and the chronometer error is 01m 17s fast. The variation is 13.5&deg;W. What is the deviation of the standard compass?

On 1 September your 1115 zone time DR position is LAT 25°20.0'N, LONG 28°24.0'W. At that time, you observe the Sun bearing 160.5°psc. The chronometer reads 01h 14m 58s, and the chronometer error is 01m 17s fast. The variation is 13.5°W. What is the deviation of the standard compass?