On 10 February in DR position LAT 25°32.0'N, LONG 135°15.0'E, you observe an amplitude of the Sun. The Sun's center is on the celestial horizon and bears 109°psc. The chronometer reads 09h 43m 25s and is 03m 20s fast. Variation in the area is 4.5°W. What is the deviation of the standard magnetic compass?

Question

On 10 February in DR position LAT 25&deg;32.0'N, LONG 135&deg;15.0'E, you observe an amplitude of the Sun. The Sun's center is on the celestial horizon and bears 109&deg;psc. The chronometer reads 09h 43m 25s and is 03m 20s fast. Variation in the area is 4.5&deg;W. What is the deviation of the standard magnetic compass?

Accepted Answer

Option A: 1.6&deg;E. Find the Sun's declination for the date and calculate the true amplitude. Compare the true amplitude to the compass amplitude (109 degrees psc) to find the compass error. Applying the 4.5 degrees West variation to the total compass error results in a deviation of 1.6 degrees East.