Navigation Problems USCG Question #644 (Set 19)

On 10 June your vessel's 0519 zone time DR position is LAT 27°07.0'N, LONG 92°10.0'W, when an amplitude of the Sun is observed. The Sun's center is on the visible horizon and bears 063.6° per standard magnetic compass. The variation in the area is 4.8°E. The chronometer reads 11h 17m 32s and is 01m 18s slow. What is the deviation of the compass?

Official USCG Answer & Rule Citation

Correct Answer: Option B — 4.8°W

Using the Nautical Almanac and latitude/time data, compute the Sun's true amplitude. The resulting true bearing compared against the magnetic bearing of 03.6°psc and corrected for 4.8°E variation establishes the compass error, isolating the deviation value to 4.8°W.

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