Navigation Problems USCG Question #1662 (Set 49)

On 11 December your 1816 ZT DR position is LAT 26°30.0'N, LONG 140°35.0'E. At that time, you observe Venus bearing 230°pgc. The chronometer reads 09h 14m 52s and the chronometer error is 01m 02s slow. The variation is 3.5°E. What is the gyro error?

Official USCG Answer & Rule Citation

Correct Answer: Option B — 3.3°E

Determine the True bearing of Venus using the calculated LHA and Declination from the Nautical Almanac. Compare this True bearing to the observed gyro bearing of 230° pgc. The difference between the True bearing and the gyro bearing provides the gyro error, which calculates to 3.3° E.

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