On 11 May in DR position LAT 28°13.7'N, LONG 168°36.3'E, you observe an amplitude of the Sun. The Sun's center is on the celestial horizon and bears 283°psc. The chronometer reads 07h 13m 19s and is 02m 56s slow. Variation in the area is 13°E. What is the deviation of the standard magnetic compass?

Correct Answer: Option D — 5.6°W

Calculate the Sun's true amplitude using the formula sin(Amp) = sin(Dec) / cos(Lat). Determine the Sun's true bearing, compare it to the compass bearing (corrected for chronometer error and time), and find the difference. Applying variation 13°E results in a deviation of 5.6°W for the standard compass.