On 12 June at 0919 zone time, your position is LAT 26°52'N, LONG 84°34'W. The chronometer reads 03h 17m 00s. Chronometer error is 01m 40s slow. At that time, an azimuth of the Sun is obtained. The bearing is 089.5° per standard magnetic compass. Variation for this area is 4.5°E. What is the deviation of the standard magnetic compass?

Question

Accepted Answer

Option D: 5.2°W. Determining deviation requires comparing standard compass bearing to true azimuth computed using standard time-sight or azimuth tables. Applying chronometer corrections and local variation per Bowditch navigation principles isolates compass deviation as 5.2°W.