Navigation Problems USCG Question #1580 (Set 47)

On 15 July in DR position LAT 22°19.0'N, LONG 154°37.0'W, you observe an amplitude of the Sun. The Sun's center is on the visible horizon and bears 298°psc. The chronometer reads 04h 45m 19s and is 01m 56s slow. Variation in the area is 7.5°W. What is the deviation of the standard magnetic compass?

Official USCG Answer & Rule Citation

Correct Answer: Option B — 3.0°E

Determine the Sun's declination and LHA. Calculate the true amplitude using sin(Amp) = sin(Dec) / cos(Lat). Convert the amplitude to a true bearing. Comparing the true bearing to the compass bearing (298° psc) and applying 7.5°W variation results in a deviation of 3.0°E.

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