On 15 October your 0325 zone time DR position is LAT 26°51.0'N, LONG 138°17.0'W. At that time, you observe Canopus bearing 167°pgc. The chronometer reads 00h 25m 36s, and the chronometer error is 00m 20s slow. The variation is 2°E. What is the gyro error?

Question

On 15 October your 0325 zone time DR position is LAT 26&deg;51.0'N, LONG 138&deg;17.0'W. At that time, you observe Canopus bearing 167&deg;pgc. The chronometer reads 00h 25m 36s, and the chronometer error is 00m 20s slow. The variation is 2&deg;E. What is the gyro error?

Accepted Answer

Option A: 1.3&deg;W. Convert chronometer time and error to obtain exact GMT. Solve the PZX navigational triangle for Canopus using standard intercept or time-azimuth methods, then compare true bearing with gyro bearing to derive gyro error.

On 15 October your 0325 zone time DR position is LAT 26&deg;51.0'N, LONG 138&deg;17.0'W. At that time, you observe Canopus bearing 167&deg;pgc. The chronometer reads 00h 25m 36s, and the chronometer error is 00m 20s slow. The variation is 2&deg;E. What is the gyro error?

On 15 October your 0325 zone time DR position is LAT 26°51.0'N, LONG 138°17.0'W. At that time, you observe Canopus bearing 167°pgc. The chronometer reads 00h 25m 36s, and the chronometer error is 00m 20s slow. The variation is 2°E. What is the gyro error?