On 17 April your 1516 zone time DR position is LAT 27°24.0'N, LONG 115°24.0'E. At that time, you observe the Sun bearing 247°psc. The chronometer reads 07h 16m 26s, and the chronometer error is 00m 32s slow. The variation is 4.5°E. What is the deviation of the standard compass?

Correct Answer: Option C — 5.4°E

Convert chronometer time to UTC using chronometer error, apply DR longitude to find Greenwich Hour Angle and LHA, and solve the navigational triangle via Pub. 229/249 for computed azimuth. Compare true azimuth against the standard compass bearing to isolate compass error, then clear variation to resolve deviation.