On 17 April your vessel's position is LAT 21°00'S, LONG 78°30'W, when an amplitude of the Sun is observed. The Sun's center is on the celestial horizon and bears 082.7° per standard magnetic compass. Variation in the area is 2.0°W. The chronometer reads 10h 59m 24s and is 01m 24s fast. What is the deviation of the compass?

Correct Answer: Option C — 2.0°W

Calculate the Sun's declination and determine the True Amplitude using the standard formula. The difference between the True Amplitude and the compass bearing provides the Compass Error. Adjusting for the 2.0°W variation, the deviation is calculated as 2.0°W, ensuring the magnetic compass is correctly aligned with the true bearing.