Navigation Problems USCG Question #1571 (Set 47)

On 17 May your 1554 zone time DR position is LAT 26°33.0'N, LONG 65°46.0'W. At that time, you observe the Sun bearing 269°psc. The chronometer reads 07h 55m 47s, and the chronometer error is 01m 14s fast. The variation is 3°W. What is the deviation of the standard magnetic compass?

Official USCG Answer & Rule Citation

Correct Answer: Option D — 7.6°E

Calculate the Sun's declination and LHA using the corrected GMT. Determine the True amplitude using sin(Amp) = sin(Dec) / cos(Lat). The difference between the True bearing and the compass bearing (269°) provides the compass error. Applying the 3°W variation to this error results in a deviation of 7.6°E.

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