On 19 November your 0146 ZT position is LAT 33°48'N, LONG 25°22'E. You observe Polaris bearing 359.8°pgc. At the time of the observation the helmsman noted that he was heading 224°pgc and 222.5°psc. The variation is 2°E. What is the deviation for that heading?

Question

On 19 November your 0146 ZT position is LAT 33&deg;48'N, LONG 25&deg;22'E. You observe Polaris bearing 359.8&deg;pgc. At the time of the observation the helmsman noted that he was heading 224&deg;pgc and 222.5&deg;psc. The variation is 2&deg;E. What is the deviation for that heading?

Accepted Answer

Option C: 1.0&deg;W. Polaris bears 000° True. A bearing of 359.8° pgc indicates a gyro error of 0.2° E. Applying this to the heading 224° pgc yields a True heading of 224.2°. Using the formula True = Compass + Variation + Deviation, 224.2° = 222.5° + 2° + Deviation, resulting in a deviation of 1.0° W.

On 19 November your 0146 ZT position is LAT 33&deg;48'N, LONG 25&deg;22'E. You observe Polaris bearing 359.8&deg;pgc. At the time of the observation the helmsman noted that he was heading 224&deg;pgc and 222.5&deg;psc. The variation is 2&deg;E. What is the deviation for that heading?

On 19 November your 0146 ZT position is LAT 33°48'N, LONG 25°22'E. You observe Polaris bearing 359.8°pgc. At the time of the observation the helmsman noted that he was heading 224°pgc and 222.5°psc. The variation is 2°E. What is the deviation for that heading?