Navigation Problems USCG Question #1627 (Set 48)

On 2 March your 2216 ZT DR position is LAT 21°20.0'S, LONG 17°10.0'W. At that time, you observe Saturn bearing 078°psc. The chronometer reads 11h 14m 04s, and the chronometer error is 02m 20s slow. The variation is 4.5°W. What is the deviation of the standard compass?

Official USCG Answer & Rule Citation

Correct Answer: Option D — 3.6°E

Calculate the true azimuth of Saturn using the Nautical Almanac. The difference between the true azimuth and the compass bearing of 078°psc yields the compass error. Adjusting for the 4.5°W variation using the standard formula Error = Variation + Deviation confirms a deviation of 3.6°E for the magnetic compass.

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