On 2 October your 1845 DR position was LAT 28°09.2'S, LONG 167°48.1'E. You observe a faint star through a hole in the clouds at a sextant altitude (hs) of 20°45.6' T, bearing 201.5°T. The index error is 1.3' off the arc, and the height of eye is 42 feet. The chronometer reads 07h 46m 19s and is 00m 51s fast. What star did you observe?

Question

Accepted Answer

Option A: Alpha Muscae. Apply index error (off the arc is added) and height of eye dip correction to sextant altitude. Convert chronometer time to GMT, calculate LHA using DR longitude, and compare computed intercept and azimuth with navigational tables to identify Alpha Muscae.