On 21 November at 2100 zone time, you depart LAT 32°12.0'N, LONG 69°26.0'W enroute to LAT 12°05.0'N, LONG 7°32.0'W. The distance is 3,519 miles, and the average speed will be 12.5 knots. What is the zone time of arrival?

Question

On 21 November at 2100 zone time, you depart LAT 32&deg;12.0'N, LONG 69&deg;26.0'W enroute to LAT 12&deg;05.0'N, LONG 7&deg;32.0'W. The distance is 3,519 miles, and the average speed will be 12.5 knots. What is the zone time of arrival?

Accepted Answer

Option C: 1830, 3 December. Calculate transit time: 3,519 miles / 12.5 knots = 281.52 hours (11 days, 17 hours, 31 minutes). Determine the zone description difference between the departure (ZD +5) and arrival (ZD 0). Adding the elapsed time and zone adjustment to the departure time yields an arrival of 1830 on 3 December.

On 21 November at 2100 zone time, you depart LAT 32&deg;12.0'N, LONG 69&deg;26.0'W enroute to LAT 12&deg;05.0'N, LONG 7&deg;32.0'W. The distance is 3,519 miles, and the average speed will be 12.5 knots. What is the zone time of arrival?

On 21 November at 2100 zone time, you depart LAT 32°12.0'N, LONG 69°26.0'W enroute to LAT 12°05.0'N, LONG 7°32.0'W. The distance is 3,519 miles, and the average speed will be 12.5 knots. What is the zone time of arrival?