On 22 October in DR position LAT 21°51.0'S, LONG 76°24.0'E, you observe an amplitude of the Sun. The Sun's center is on the visible horizon and bears 256°psc. The chronometer reads 01h 01m 25s and is 01m 15s fast. Variation for the area is 2°E. What is the deviation of the standard magnetic compass?

Correct Answer: Option A — 0.3°W

Calculate the Sun's declination and LHA using the Nautical Almanac. Determine the True Amplitude (sin Amp = sin Dec / cos Lat). Compare the True Amplitude to the compass bearing to find Compass Error. Applying variation of 2°E to the Compass Error yields a deviation of 0.3°W.