On 22 October in DR position LAT 21°51.0'S, LONG 76°24.0'E, you observe an amplitude of the Sun. The Sun's center is on the visible horizon and bears 256°psc. The chronometer reads 01h 01m 25s and is 01m 15s fast. Variation for the area is 2°E. What is the deviation of the standard magnetic compass?

Question

On 22 October in DR position LAT 21&deg;51.0'S, LONG 76&deg;24.0'E, you observe an amplitude of the Sun. The Sun's center is on the visible horizon and bears 256&deg;psc. The chronometer reads 01h 01m 25s and is 01m 15s fast. Variation for the area is 2&deg;E. What is the deviation of the standard magnetic compass?

Accepted Answer

Option B: 0.3&deg;W. Calculate the Sun's declination and LHA. Determine the true amplitude using sin(Amp) = sin(Dec) / cos(Lat). Convert the amplitude to a true bearing. Comparing this to the compass bearing (256° psc) and applying 2°E variation results in a deviation of 0.3°W.