On 23 August at 0604 ZT, in DR position LAT 16°42.3'S, LONG 28°19.3'W, you observed an amplitude of the Sun. The lower limb was a little above the horizon, and the Sun bore 076.0°pgc. At the time of the observation, the helmsman reported that he was heading 143°pgc and 167° per standard magnetic compass. The variation in the area was 23°W. What were the gyro error and deviation for that heading?
Official USCG Answer & Rule Citation
Correct Answer: Option D — 2°E GE, 1°E DEV
Calculate the Sun's amplitude to find the true bearing. Compare the true bearing to the gyro bearing (076°pgc) to determine the gyro error of 2°E. Convert the true bearing to magnetic using 23°W variation. Compare the magnetic bearing to the compass bearing (167°psc) to find 1°E deviation.
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